Diablo® III

48÷2(9+3) = ? cont.

Posts: 204
Original thread:
http://us.battle.net/d3/en/forum/topic/5730076080

@above, would you solve the problem the same if 48/2(12) was 48/2x?


In this line form yes.
48/2x = 288
24x =288
x=12

Like I said if you want it to be 48 over 2x you have to write it 48/(2x).

Now it's bedtime. I'll check this thread tomorrow at work. Might give me something to do.
Edited by rand0m#1596 on 6/11/2012 10:37 PM PDT
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90 Human Warrior
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Posts: 240
http://knowyourmeme.com/memes/48293
...
lol
it's so sad how well this worked. A+ troll.
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"When you assume you make an !@#.. OUTTA YO SELF!"- Come on, who gets the reference?

Anyway, I can't help but throw my two cents out here.

I just graduated high school, I've always scored in the top 99% on standardized tests and such, and colleges haven't stopped spamming my $%^-*!@ e-mail since my SAT scores came in. I'm neither a math major, nor an engineer, but the simple order of operations is still fresh in my mind.

My strength has always lied in problem solving and critical thinking, and while most people don't give a #$%^ and will continue on with the answer they think is right, I've got to take the pragmatic route and show that the answer is -----> 288

There is no, "it's assumed that this and that", or "there are two answers".

NO, THERE AREN'T.

Many people have stated this already, but multiplication and division are of equal precedence, and for that reason you solve from left to right after making sure parenthesis and exponents are taken care of.

Thus, 48/2(9+3) becomes 48/2(12). There, now that parenthesis are taken care of and there are no exponents, solve left to right and divide 48 by 2 and get 24(12). You then multiply 24 by 12 and get 288.

Thank you for reading my post in it's entirety, and I hope some of you have learned something.
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90 Dwarf Hunter
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Posts: 199
posting this again because it was at the very end of the previous thread
48÷2(9+3) = ?

48/2(12), we can all agree that is what happens

the people that say two, are making the mistake by multiplying a number on the denominator with a number in the numerator to get 48/24=2, but in order for it to be 2 it would have to be 48/[2(12)], that would be 2.

48/2(12) = 288, end of story

48/2 X 12/1, read it that way, 48/1 X 12/2 or that way and you will never get it wrong
Edited by Kell#1134 on 6/11/2012 11:11 PM PDT
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Posts: 196
The issue here is not whether the answer is actually 2 or 288
It is that math has apparently been taught differently to so many people

So the real question is whether or not 2(9+3) has any more preferment to going 1st in a math problem than 2*(9+3)

Indeed i do believe that many people would argue that the 2 should be distributed into the parenthesis. making it 2(9+3) = (18+6)
Thus the overall equation would become 48÷(18+6) = 48÷24 = 2

However in this problem the 2 is not distributed in and indeed there is an implied multiplication sign.
48÷2*(9+3) , which does equal 288.... or does it.
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Posts: 196
"48/x(9+3) = 48/1 * 1/x(12) = 48/1 * 1/x *1/12"

how did you get * 1/12 here and not just *12/1 ?
1/x(12) does not stick 12 on the denumerator.
Thus using your own logic, and the corrected 12/1 instead of 1/12
we get 48/1 * 1/x * 12/1. where x = 2 making the answer 288, like it really is =)
Edited by Schlepian#1420 on 6/11/2012 11:44 PM PDT
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[quote]
There is no division in the new problem. The results of the first equation are the same as the results for the 3rd equation for any given value of x.

x = 2 for the current problem

48/1 * 1/(2) * 1/12
= 2

Thus, the answer is 2.


You added a parenthesis around the 2 that wasn't previously a part of the problem, thus changing the result.

Not gonna fool me you sly son of a gun
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Posts: 196
48/1 * 1/x * 12/1 = 48 * 12 * 1/x = 576/x or 48(9+3)/x != 48/x(9+3)

Are you saying that this statement is false?. For what values of x is 48(9+3)/x = 48/x(9+3) not a true statement?
Let's make it simpler.
48*12÷x = 48÷x*12 when is that inaccurate?
Edited by Schlepian#1420 on 6/11/2012 11:53 PM PDT
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Posts: 39
You edited your post, but did not see my proof on concept:

if 12/1 not 1/12:

48/1 * 1/x * 12/1 = 48 * 12 * 1/x = 576/x or 48(9+3)/x != 48/x(9+3)


You are wrong: 48(9+3)/x = 48/x(9+3) = (9+3)/x*48 = 1/x(9+3)48 These forms are actually equal always. Your still always dividing by x no matter how you rearrange the problem.

Its called the commutative property.
Edited by Gilager#1578 on 6/12/2012 12:06 AM PDT
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so I haven't read everything but seriously everyone is saying PEMDAS or if your British or something then BEDMAS(I believe). I think everyone is forgetting about the first one of the order of operations... Parenthesis. When you use parenthesis you distribute the 2, so you can either do that before or after adding the 9 and three... 48/(18+6) or 48/2(12) making the parenthesis still there, they dont go away and make a multiplication sign. this is basic skills that aren't taught well in any education system. You can also think of this as a fraction, as with any division. so 48 is the numerator and 2(9+3) is the denominator which brings in how wrong some people can misuse the calculator. you need the parenthesis around the 2(9+3), like: (2(9+3)) showing that you don't want it to do that fraction prematurely and have a fraction of 48/2 and then a fraction of 1/(9+3).... sigh, no sense making in that at all... I know they didn't teach how to use a calculator in High School nor 6th grade like some of you are saying as well but it was implied that you could pick up on it..

Original thread:
http://us.battle.net/d3/en/forum/topic/5730076080

@above, would you solve the problem the same if 48/2(12) was 48/2x?


In this line form yes.
48/2x = 288
24x =288
x=12

Like I said if you want it to be 48 over 2x you have to write it 48/(2x).

Now it's bedtime. I'll check this thread tomorrow at work. Might give me something to do.


so with this example you will want to keep the x with the 2..... or you can keep the x in the denominator making it 24/x=288 which makes x to come out to be 24/288=x
48
--- = 288
2x
STOP thinking of this as a linear equation and start thinking of it as a fraction and it will make much more sense
48
--- =2 x=12 !!!!!!!!!!!!!!!!!!!!!!
2x

btw this is Algebra which in the USA is taught in the 8th or 9th grade... (depending on stupidity...)
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"When you assume you make an !@#.. OUTTA YO SELF!"- Come on, who gets the reference?

I just graduated high school, I've always scored in the top 99% on standardized tests and such, and colleges haven't stopped spamming my $%^-*!@ e-mail since my SAT scores came in. I'm neither a math major, nor an engineer, but the simple order of operations is still fresh in my mind.

Thank you for reading my post in it's entirety, and I hope some of you have learned something.


You really call yourself smart? You're a high school student that barely graduated, and you think that you are smart? Why, because they dumb down SAT tests so that everyone can pass it and make something of themselves at McDonald's?.... You forgot about the distribution of the 2(9+3)... Surely your algebra teacher should have taught you that, or possibly the SAT test but no..

Going through 3 years of College (and graduated early) with a BS in Actuary Mathematics, I have a thorough understanding of the concept of a fraction as well as proper operations such as what is implied in the Mathematical community of a parenthesis.

I wanna quote a very famous professor now, "I don't want to live on this planet anymore."
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Posts: 39
Order of Operations.

(48(9+3)/x)/(48/x(9+3)) = 0
(576/x)/(48/9x +3x) = 0
(576/x)/(48/12x) = 0
576/x ÷ 4/x != 0

Therefore not equal.


This is wrong. Those are not the same thing. You made a mistake.
48/x(9+3) = 48/x*12 not 48/(9x+3x) there is no parentheses around the x(9+3) therefore when you do 48/x as the first operation you can not take that same x and do x(9+3) because you already used it in the first operation. Therefore it should have looked like so.
(48(9+3)/x)/(48/x(9+3)) = 0
(576/x)/(48/x*12) = 0
(576/x)/(576x) = 0
576/x ÷ 576/x = 0
Edited by Gilager#1578 on 6/12/2012 12:25 AM PDT
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Posts: 39
This is patently false. Relearn OoO plz. x(9+3) is solved first.

= 9x + 3x
= 12x


and where is the parentheses around x(9+3) making it the first operation to solve? Sorry the distributive property does not apply here because 48/x(9+3) != 48/(x(9+3)). You assumed (x(9+3)) when that was not written at all.

Therefore 48(9+3)/x = 48/x(9+3) = (9+3)/x*48 = 1/x(9+3)48 is still correct due to commutative law.

I also corrected this to show you your error.
(48(9+3)/x)/(48/x(9+3)) = 0
(576/x)/(48/x*12) = 0
(576/x)/(576x) = 0
576/x ÷ 576/x = 0

48/x(9+3) <- no parentheses around x(9+3) so according to order of operations (9+3) is first which makes it 48/x*12 = 576/x so please relearn.
Edited by Gilager#1578 on 6/12/2012 12:42 AM PDT
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Posts: 196
just because you learned to distribute in your 8th and 9th grade algebra classes does not make that the correct order of operations.
and as for making it into a fraction it would become
48
--- (9+3)
2
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