ok, So I'm going to try to explain this situation using math.

So at mp7 drops rate per run is 70%.

I'm going to assume that the drop rate for each run is independent from each other.

So with this assumption.

the probability of get zero keys after 2 runs is .3*.3, so this equal to 9%, so 9% percent of the time over 2 runs you will get 0 keys. (on average)

now we do 7 runs. So the probability of getting 0 key over 7 runs is: .3*.3*.3*.3*.3*3*.3 =0.02% so this is pretty rare event.(but still possible). the interpretation of this is. If you do 10 000 batch of 7 runs. 2 times you will get 0 keys, (on average)

Now this dude say he got 2 key out of 20 runs. The probability of such an event is. 20!/(18!*2!)*0.7*0.7*(0.3)^18 = 0.0000036% , now that is pretty rare!!!(but still possible)

Hope this help understanding the situation...

So at mp7 drops rate per run is 70%.

I'm going to assume that the drop rate for each run is independent from each other.

So with this assumption.

the probability of get zero keys after 2 runs is .3*.3, so this equal to 9%, so 9% percent of the time over 2 runs you will get 0 keys. (on average)

now we do 7 runs. So the probability of getting 0 key over 7 runs is: .3*.3*.3*.3*.3*3*.3 =0.02% so this is pretty rare event.(but still possible). the interpretation of this is. If you do 10 000 batch of 7 runs. 2 times you will get 0 keys, (on average)

Now this dude say he got 2 key out of 20 runs. The probability of such an event is. 20!/(18!*2!)*0.7*0.7*(0.3)^18 = 0.0000036% , now that is pretty rare!!!(but still possible)

Hope this help understanding the situation...